2(x^2+5x+6)=-x^2-2x

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Solution for 2(x^2+5x+6)=-x^2-2x equation: 



2(x^2+5x+6)=-x^2-2x

We move all terms to the left:

2(x^2+5x+6)-(-x^2-2x)=0

We multiply parentheses

-(-x^2-2x)+2x^2+10x+12=0

We get rid of parentheses

x^2+2x^2+2x+10x+12=0

We add all the numbers together, and all the variables

3x^2+12x+12=0

a = 3; b = 12; c = +12;
Δ = b2-4ac
Δ = 122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{6}=-2$

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